Question

name alisson serrano pd. 4 date 1-16-26
wildfires final project - symbolic representation
the unbalanced chemical equation for a wild fire is as follows:
c₆h₁₂o₆ + o₂ → co₂ + h₂o
using the drawing method, balance the chemical equation of a wildfire. show your work below:

□ complete the balanced chemical equation below:
c₆h₁₂o₆ + o₂ → co₂ + h₂o

Explanation:

Step1: Balance Carbon atoms

In \( \ce{C6H12O6} \), there are 6 C atoms. So, we need 6 \( \ce{CO2} \) molecules (since each \( \ce{CO2} \) has 1 C atom) to balance C.
\( \ce{C6H12O6 + O2 -> 6CO2 + H2O} \)

Step2: Balance Hydrogen atoms

In \( \ce{C6H12O6} \), there are 12 H atoms. Each \( \ce{H2O} \) has 2 H atoms, so we need \( \frac{12}{2} = 6 \) \( \ce{H2O} \) molecules.
\( \ce{C6H12O6 + O2 -> 6CO2 + 6H2O} \)

Step3: Balance Oxygen atoms

On the right side: \( 6\ce{CO2} \) has \( 6 \times 2 = 12 \) O atoms, and \( 6\ce{H2O} \) has \( 6 \times 1 = 6 \) O atoms. Total O on right: \( 12 + 6 = 18 \).
On the left side: \( \ce{C6H12O6} \) has 6 O atoms, so \( \ce{O2} \) must provide \( 18 - 6 = 12 \) O atoms. Since each \( \ce{O2} \) has 2 O atoms, we need \( \frac{12}{2} = 6 \) \( \ce{O2} \) molecules.
\( \ce{C6H12O6 + 6O2 -> 6CO2 + 6H2O} \)

Answer:

\( \boldsymbol{1} \) \( \ce{C6H12O6} \) + \( \boldsymbol{6} \) \( \ce{O2} \) \( \boldsymbol{
ightarrow} \) \( \boldsymbol{6} \) \( \ce{CO2} \) + \( \boldsymbol{6} \) \( \ce{H2O} \)