Question

name: asil abcmatar

1. 16 °c
2. 114°f
3. 19°c
4. 99° f
5. 16°f
6. 24°c
7. 28°c
8. 43°c
9. 80°f
10. 94°f
11. 73°f
12. 6°c
13. 41°c

Explanation:

Step1: Recall temperature - conversion formula

The formula to convert Celsius (C) to Fahrenheit (F) is $F=\frac{9}{5}C + 32$, and to convert Fahrenheit to Celsius is $C=\frac{5}{9}(F - 32)$.

Step2: Convert 16°C to Fahrenheit

Substitute $C = 16$ into $F=\frac{9}{5}C+32$. So $F=\frac{9}{5}\times16 + 32=\frac{144}{5}+32=28.8 + 32=60.8^{\circ}F$.

Step3: Convert 114°F to Celsius

Substitute $F = 114$ into $C=\frac{5}{9}(F - 32)$. So $C=\frac{5}{9}(114 - 32)=\frac{5}{9}\times82=\frac{410}{9}\approx45.6^{\circ}C$.

Step4: Convert 19°C to Fahrenheit

Substitute $C = 19$ into $F=\frac{9}{5}C + 32$. So $F=\frac{9}{5}\times19+32=\frac{171}{5}+32 = 34.2+32=66.2^{\circ}F$.

Step5: Convert 99°F to Celsius

Substitute $F = 99$ into $C=\frac{5}{9}(F - 32)$. So $C=\frac{5}{9}(99 - 32)=\frac{5}{9}\times67=\frac{335}{9}\approx37.2^{\circ}C$.

Step6: Convert 16°F to Celsius

Substitute $F = 16$ into $C=\frac{5}{9}(F - 32)$. So $C=\frac{5}{9}(16 - 32)=\frac{5}{9}\times(- 16)=-\frac{80}{9}\approx - 8.9^{\circ}C$.

Step7: Convert 24°C to Fahrenheit

Substitute $C = 24$ into $F=\frac{9}{5}C + 32$. So $F=\frac{9}{5}\times24+32=\frac{216}{5}+32=43.2 + 32=75.2^{\circ}F$.

Step8: Convert 28°C to Fahrenheit

Substitute $C = 28$ into $F=\frac{9}{5}C + 32$. So $F=\frac{9}{5}\times28+32=\frac{252}{5}+32=50.4+32 = 82.4^{\circ}F$.

Step9: Convert 43°C to Fahrenheit

Substitute $C = 43$ into $F=\frac{9}{5}C + 32$. So $F=\frac{9}{5}\times43+32=\frac{387}{5}+32=77.4+32 = 109.4^{\circ}F$.

Step10: Convert 80°F to Celsius

Substitute $F = 80$ into $C=\frac{5}{9}(F - 32)$. So $C=\frac{5}{9}(80 - 32)=\frac{5}{9}\times48=\frac{240}{9}\approx26.7^{\circ}C$.

Step11: Convert 94°F to Celsius

Substitute $F = 94$ into $C=\frac{5}{9}(F - 32)$. So $C=\frac{5}{9}(94 - 32)=\frac{5}{9}\times62=\frac{310}{9}\approx34.4^{\circ}C$.

Step12: Convert 73°F to Celsius

Substitute $F = 73$ into $C=\frac{5}{9}(F - 32)$. So $C=\frac{5}{9}(73 - 32)=\frac{5}{9}\times41=\frac{205}{9}\approx22.8^{\circ}C$.

Step13: Convert 6°C to Fahrenheit

Substitute $C = 6$ into $F=\frac{9}{5}C + 32$. So $F=\frac{9}{5}\times6+32=\frac{54}{5}+32 = 10.8+32=42.8^{\circ}F$.

Step14: Convert 41°C to Fahrenheit

Substitute $C = 41$ into $F=\frac{9}{5}C + 32$. So $F=\frac{9}{5}\times41+32=\frac{369}{5}+32=73.8+32 = 105.8^{\circ}F$.

Answer:

1. $60.8^{\circ}F$
2. $\approx45.6^{\circ}C$
3. $66.2^{\circ}F$
4. $\approx37.2^{\circ}C$
5. $\approx - 8.9^{\circ}C$
6. $75.2^{\circ}F$
7. $82.4^{\circ}F$
8. $109.4^{\circ}F$
9. $\approx26.7^{\circ}C$
10. $\approx34.4^{\circ}C$
11. $\approx22.8^{\circ}C$
12. $42.8^{\circ}F$
13. $105.8^{\circ}F$