Question

name:date: february 10, 2016 period: 3/4/4bassignment - probability, day 5experimental probabilitygrade 7lowman educationrecent1. at a dinner, guests choose one entrée and one side item. what is the probability that a guest will randomly choose steak for the entrée and a potato for the side?menuentréesteakchickenfishsidesaladpotatoveggietoday

Explanation:

Step1: Count total entrée options

There are 3 entrée options: Steak, Chicken, Fish.

Step2: Count total side options

There are 3 side options: Salad, Potato, Veggie.

Step3: Calculate total meal combinations

Total combinations = Number of entrées × Number of sides
$\text{Total combinations} = 3 \times 3 = 9$

Step4: Count favorable combinations

Favorable case: Steak (1 entrée) + Potato (1 side), so 1 favorable combination.

Step5: Compute probability

Probability = $\frac{\text{Favorable combinations}}{\text{Total combinations}}$
$\text{Probability} = \frac{1}{9}$

Answer:

$\frac{1}{9}$