Question

1. name the following binary ionic compounds.

a. sri₂
b. li₂o
c. agf
d. fecl₃
e. cuo

1. name the following ionic compounds that contain polyatomic ions.

a. cuso₄
b. mg(oh)₂
c. nahco₃
d. caco₃
e. nano₃
f. baso₄
g. alpo₄
h. kclo₃
ions.
h₂po₄⁻ hydrogen phosphate
hpo₄²⁻ hydrogen phosphate
po₄³⁻ phosphate
cn⁻ cyanide
oh⁻ hydroxide
hso₄⁻ hydrogen sulfate
so₄²⁻ sulfate
so₃²⁻ sulfite
no₃⁻ nitrate
no₂⁻ nitrite
nh₄⁺ ammonium
ion
common polyatomic ions
name
o₂²⁻ peroxide
cro₄²⁻ chromate
cr₂o₇²⁻ dichromate
mno₄⁻ permanganate
c₂h₃o₂⁻ acetate
clo₄⁻ perchlorate
clo₃⁻ chlorate
clo₂⁻ chlorite
clo⁻ hypochlorite
hco₃⁻ hydrogen carbonate
co₃²⁻ carbonate
ion
name

Explanation:

Step1: Name binary ionic compounds

For binary ionic compounds, name the metal first and then the non - metal with the ending changed to “-ide”.

• a. $SrI_2$: Strontium is the metal and iodine is the non - metal. So it is strontium iodide.
• b. $Li_2O$: Lithium is the metal and oxygen is the non - metal. So it is lithium oxide.
• c. $AgF$: Silver is the metal and fluorine is the non - metal. So it is silver fluoride.
• d. $FeCl_3$: Iron has a + 3 charge here, so it is iron(III) chloride.
• e. $CuO$: Copper has a + 2 charge here, so it is copper(II) oxide.

Step2: Name ionic compounds with polyatomic ions

Name the metal first, then the polyatomic ion.

• a. $CuSO_4$: Copper is the metal and $SO_4^{2 - }$ is sulfate. So it is copper(II) sulfate.
• b. $Mg(OH)_2$: Magnesium is the metal and $OH^-$ is hydroxide. So it is magnesium hydroxide.
• c. $NaHCO_3$: Sodium is the metal and $HCO_3^-$ is hydrogen carbonate. So it is sodium hydrogen carbonate.
• d. $CaCO_3$: Calcium is the metal and $CO_3^{2 - }$ is carbonate. So it is calcium carbonate.
• e. $NaNO_3$: Sodium is the metal and $NO_3^-$ is nitrate. So it is sodium nitrate.
• f. $BaSO_4$: Barium is the metal and $SO_4^{2 - }$ is sulfate. So it is barium sulfate.
• g. $AlPO_4$: Aluminum is the metal and $PO_4^{3 - }$ is phosphate. So it is aluminum phosphate.
• h. $KClO_3$: Potassium is the metal and $ClO_3^-$ is chlorate. So it is potassium chlorate.

Answer:

a. Strontium iodide
b. Lithium oxide
c. Silver fluoride
d. Iron(III) chloride
e. Copper(II) oxide
a. Copper(II) sulfate
b. Magnesium hydroxide
c. Sodium hydrogen carbonate
d. Calcium carbonate
e. Sodium nitrate
f. Barium sulfate
g. Aluminum phosphate
h. Potassium chlorate