Question

name the following compounds
1 cf₄
2 ba₃(po₃)₂
3 cu(hso₃)₂
4 p₂s₄
a. phosphorus sulfide b. phosphorus tetrasulfide c. diphosphorus tetrasulfide
d. phosphorus (ii) sulfide e. copper hydrogen sulfite f. copper hydrogen sulfate
g. copper (ii) hydrogen sulfate h. copper (ii) hydrogen sulfite i. barium phosphite
j. barium phosphate k. barium (iii) phosphite l. barium (ii) phosphite
m. carbon fluoride n. carbon tetrafluoride o. monocarbon tetrafluoride
p. carbon (iv) fluoride q. carbon (iv) tetrafluoride r. kim kardashian

Explanation:

1. For $CF_4$, carbon is the first - named element and there is 1 carbon atom, and 4 fluorine atoms. The prefix for 4 is 'tetra -', so it is carbon tetrafluoride.
2. For $Ba_3(PO_3)_2$, $Ba$ is barium, and the poly - atomic ion $(PO_3)^{2 - }$ is phosphite. The compound is barium phosphite.
3. For $Cu(HSO_3)_2$, copper has a + 2 oxidation state here (since $(HSO_3)^-$ has a - 1 charge and there are 2 of them), and $(HSO_3)^-$ is hydrogen sulfite ion. So it is copper(II) hydrogen sulfite.
4. For $P_2S_4$, there are 2 phosphorus atoms (prefix 'di -') and 4 sulfur atoms (prefix 'tetra -'), so it is diphosphorus tetrasulfide.

Answer:

1. N. carbon tetrafluoride
2. I. barium phosphite
3. H. copper(II) hydrogen sulfite
4. C. diphosphorus tetrasulfide