Question

name: graphing data directions: use the table of data to create a line graph to show how the data changes over time. label each axis, plot points, and connect the points with a line. 1. what is the difference between the highest average temperature and the lowest average temperature? 2. between which two months did the average high temperature remain the same? 1. 1 kg = g 2. 67 cl = ml 3. 0.276 hm = cm 4. 137 dag = dg 5. 0.032 kl = cl 6. 49.1 l = cl

Explanation:

Step1: Identify highest and lowest temps

From the temperature - month table.

Step2: Calculate temperature difference

\(80 - 62\).

Step3: Find months with same temp

Check each month's temp value.

Step4: Convert kg to g

Use conversion factor \(1\ kg = 1000\ g\).

Step5: Convert cl to ml

Use conversion factor \(1\ cl = 10\ ml\).

Step6: Convert hm to cm

Use conversion factor \(1\ hm = 10000\ cm\).

Step7: Convert dag to dg

Use conversion factor \(1\ dag = 10\ dg\).

Step8: Convert kl to cl

Use conversion factor \(1\ kl = 100000\ cl\).

Step9: Convert l to cl

Use conversion factor \(1\ l = 100\ cl\).

Answer:

1.

• First, find the highest and lowest temperatures from the table. The highest average - high temperature is 80 (in month 6) and the lowest is 62 (in month 2 and 12).
• Then calculate the difference: \(80 - 62=18\).

1. The average high temperature is 74 in both month 7 and month 8.

3.

• Since \(1\ kg = 1000\ g\), the answer is 1000.
• Since \(1\ cl=10\ ml\), then \(67\ cl = 67\times10 = 670\ ml\).
• Since \(1\ hm = 10000\ cm\), then \(0.276\ hm=0.276\times10000 = 2760\ cm\).
• Since \(1\ dag = 10\ dg\), then \(137\ dag=137\times10 = 1370\ dg\).
• Since \(1\ kl = 100000\ cl\), then \(0.032\ kl=0.032\times100000 = 3200\ cl\).
• Since \(1\ l = 100\ cl\), then \(49.1\ l=49.1\times100 = 4910\ cl\).