Question

name: lucy egrions
unit 1: atomic structure
remember:

• the # of protons is the atomic number (does not change!!)
• the # of electrons is usually the same as the atomic number (unless the element is chemically bonded)
• the atomic mass is the number of protons and the number of neutrons
• the # of neutrons can be different (these are called isotopes!)

atomic structure and isotopes
draw the model of an aluminum atom; indicate the correct number of protons, neutrons, and electrons.

identify the #p, #n, and #e
$_{8}^{16}$o
$_{83}^{210}$bi

write the symbol

• 36p, 48n, and 36e
• 52p, 75n, and 55e
• 22p, 26n, and 20e

Explanation:

Step1: Solve for $_8^{16}\text{O}$ (p,n,e)

Protons ($p$) = atomic number = $8$; Neutrons ($n$) = mass number - protons = $16-8=8$; Electrons ($e$) = protons (neutral atom) = $8$

Step2: Solve for $_{83}^{210}\text{Bi}$ (p,n,e)

Protons = atomic number = $83$; Neutrons = $210-83=127$; Electrons = protons = $83$

Step3: Write symbol for 36p,48n,36e

Atomic number = 36 (Krypton, Kr); Mass number = $36+48=84$; Symbol: $_{36}^{84}\text{Kr}$

Step4: Write symbol for 52p,75n,55e

Atomic number = 52 (Tellurium, Te); Mass number = $52+75=127$; Charge = $55-52=+3$; Symbol: $_{52}^{127}\text{Te}^{3+}$

Step5: Write symbol for 22p,26n,20e

Atomic number = 22 (Titanium, Ti); Mass number = $22+26=48$; Charge = $20-22=-2$; Symbol: $_{22}^{48}\text{Ti}^{2+}$

Step6: Aluminum atom model details

Aluminum: $_{13}^{27}\text{Al}$; $p=13$, $n=27-13=14$, $e=13$. Model: Nucleus with 13p+14n; electron shells: 2, 8, 3 electrons.

Answer:

1. Identify #p, #n, #e:

• $_8^{16}\text{O}$: 8 protons, 8 neutrons, 8 electrons
• $_{83}^{210}\text{Bi}$: 83 protons, 127 neutrons, 83 electrons

2. Write the symbol:

• 36p, 48n, 36e: $_{36}^{84}\text{Kr}$
• 52p, 75n, 55e: $_{52}^{127}\text{Te}^{3+}$
• 22p, 26n, 20e: $_{22}^{48}\text{Ti}^{2+}$

3. Aluminum atom model:

Nucleus contains 13 protons and 14 neutrons. 3 electron shells: first shell has 2 electrons, second shell has 8 electrons, third shell has 3 electrons.