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Question
nc math 3 - binns thompson functions skills drill
functions skills drill
due sep 4 by 11:59pm points 30
submitting an external tool
available sep 4 at 11am - oct 24 at 11:59pm
find the inverse function of the function $f(x)=\frac{1}{4}x + 5$.
answer
$f^{-1}(x)=-4x - 5$
$f^{-1}(x)=4x - 20$
$f^{-1}(x)=-4x - 20$
$f^{-1}(x)=4x - 5$
Step1: Set \(y = f(x)\)
Let \(y=\frac{1}{4}x + 5\).
Step2: Solve for \(x\) in terms of \(y\)
First, subtract 5 from both sides: \(y - 5=\frac{1}{4}x\). Then multiply both sides by 4 to get \(x = 4(y - 5)=4y-20\).
Step3: Replace \(x\) with \(f^{-1}(x)\) and \(y\) with \(x\)
We have \(f^{-1}(x)=4x - 20\).
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B. \(f^{-1}(x)=4x - 20\)