Question

ne:
\frac{32x^{3}y^{2}z^{5}}{-8xyz^{2}}

Explanation:

Step1: Simplify the coefficient

Divide 32 by -8.
$\frac{32}{-8} = -4$

Step2: Simplify the \(x\)-term

Use the rule $\frac{x^m}{x^n}=x^{m - n}$. For \(x\), we have $x^{3-1}=x^2$.

Step3: Simplify the \(y\)-term

Using the same exponent rule for \(y\), $y^{2 - 1}=y^1 = y$.

Step4: Simplify the \(z\)-term

For \(z\), $z^{5 - 2}=z^3$.

Step5: Combine all simplified terms

Multiply the coefficient, \(x\)-term, \(y\)-term, and \(z\)-term together: \(-4\times x^2\times y\times z^3=-4x^2yz^3\)

Answer:

\(-4x^2yz^3\)