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complete the statement for the rational expression \\(\frac{x^3 + 6x^2 + 11x + 6}{x + 2}\\).
use factoring techniques to easily manipulate the expression.
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\after applying factoring techniques on the given expression, the quotient is \\(square\\) and the remainder is \\(square\\).\
Step1: Factor numerator by grouping
First, group terms in the numerator:
$x^3+6x^2+11x+6 = (x^3+6x^2)+(11x+6)$
Factor common terms from each group:
$= x^2(x+6) + 1(11x+6)$
Instead, use polynomial division or recognize $x=-2$ is a root (since $(-2)^3+6(-2)^2+11(-2)+6 = -8+24-22+6=0$), so $(x+2)$ is a factor. Perform polynomial long division of $x^3+6x^2+11x+6$ by $x+2$.
Step2: Polynomial division setup
Divide $x^3$ by $x$ to get $x^2$. Multiply $(x+2)$ by $x^2$: $x^3+2x^2$. Subtract from numerator:
$(x^3+6x^2+11x+6)-(x^3+2x^2) = 4x^2+11x+6$
Step3: Continue polynomial division
Divide $4x^2$ by $x$ to get $4x$. Multiply $(x+2)$ by $4x$: $4x^2+8x$. Subtract:
$(4x^2+11x+6)-(4x^2+8x) = 3x+6$
Step4: Final division step
Divide $3x$ by $x$ to get $3$. Multiply $(x+2)$ by $3$: $3x+6$. Subtract:
$(3x+6)-(3x+6) = 0$
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After applying factoring techniques on the given expression, the quotient is $x^2+4x+3$ and the remainder is $0$.