Question

ns w/ distribution (lev 3)
question in this section.
3 = 3x + 2(-9x + 9) - 9

Explanation:

Step1: Expand the expression

First, expand $2(-9x + 9)$ using the distributive - property $a(b + c)=ab+ac$. Here, $a = 2$, $b=-9x$, and $c = 9$. So, $2(-9x + 9)=-18x+18$. The original equation $3 = 3x+2(-9x + 9)-9$ becomes $3 = 3x-18x + 18-9$.

Step2: Combine like - terms

Combine the $x$ terms and the constant terms on the right - hand side. $3x-18x=-15x$ and $18 - 9 = 9$. So the equation is $3=-15x + 9$.

Step3: Isolate the variable term

Subtract 9 from both sides of the equation. $3-9=-15x+9 - 9$. This simplifies to $-6=-15x$.

Step4: Solve for $x$

Divide both sides of the equation by $-15$. $x=\frac{-6}{-15}=\frac{2}{5}$.

Answer:

$x=\frac{2}{5}$