Question

at one point in space, the direction of the electric field vector is given in the cartesian system by the unit vector \\(\hat{\mathbf{e}} = \frac{8}{\sqrt{73}} \mathbf{i} - \frac{3}{\sqrt{73}} \mathbf{j}\\). if the magnitude of the electric field vector is \\(e = 370.0\\) v/m, what are the scalar components \\(e_x\\), \\(e_y\\), and \\(e_z\\) of the electric field vector \\(\vec{\mathbf{e}}\\) at this point (in v/m)?
\\(e_x = \\) \\(\boxed{}\\) v/m
\\(e_y = \\) \\(\boxed{}\\) v/m
\\(e_z = \\) \\(\boxed{}\\) v/m
what is the direction angle \\(\theta_e\\) of the electric field vector at this point (in degrees counterclockwise from the +x - axis)?
\\(\theta_e = \\) \\(\boxed{}\\) ° counterclockwise from the +x - axis

Explanation:

Answer:

$E_x = 346.4$ V/m
$E_y = -129.9$ V/m
$E_z = 0$ V/m
$\theta_E = 339.4^\circ$ counterclockwise from the $+x$-axis