Question

1. one straight section of road rises from an elevation of 1070 m to 1132 m. the run is approximately 1.3 km. what is the percent grade of the road? round to the nearest tenth. (hint: notice the units are not the same) 1000 m = 1 km

Explanation:

Step1: Calculate the rise

The road rises from an elevation of 1070 m to 1132 m. So the rise $y=1132 - 1070=62$ m.

Step2: Convert the run to meters

The run is 1.3 km. Since 1 km = 1000 m, the run $x = 1.3\times1000=1300$ m.

Step3: Calculate the percent - grade formula

The percent - grade formula is $\text{Percent Grade}=\frac{y}{x}\times100\%$. Substitute $y = 62$ m and $x = 1300$ m into the formula: $\text{Percent Grade}=\frac{62}{1300}\times100\%$.

Step4: Simplify the expression

$\frac{62}{1300}\times100\%=\frac{6200}{1300}\% \approx 4.8\%$.

Answer:

4.8%