Question

is the order pair a solution to the system?(4, 1)$x + 2y = 6$ $3x + y = 11LXB0x + 3y=6$(- 2,1)$5x - 2y = - 12$ $x + 3y = 1$(4, - 3)$- 3x + 2y = - 18$ $6x - y = 27$(- 4, - 6)$3x - y = 6$ $- x + 2y = 8$

Explanation:

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For ordered pair $(4, 1)$

Step1: Substitute into $x+2y=6$

$4 + 2(1) = 4 + 2 = 6$

Step2: Substitute into $3x+y=11$

$3(4) + 1 = 12 + 1 = 13
eq 11$
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For ordered pair $(-2, 1)$

Step1: Substitute into $5x-2y=-12$

$5(-2) - 2(1) = -10 - 2 = -12$

Step2: Substitute into $x+3y=1$

$-2 + 3(1) = -2 + 3 = 1$
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For ordered pair $(4, -3)$

Step1: Substitute into $-3x+2y=-18$

$-3(4) + 2(-3) = -12 - 6 = -18$

Step2: Substitute into $6x-y=27$

$6(4) - (-3) = 24 + 3 = 27$
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For ordered pair $(-4, -6)$

Step1: Substitute into $3x-y=6$

$3(-4) - (-6) = -12 + 6 = -6
eq 6$

Step2: Substitute into $-x+2y=8$

$-(-4) + 2(-6) = 4 - 12 = -8
eq 8$

Answer:

1. For $(4, 1)$: No, it is not a solution to the system.
2. For $(-2, 1)$: Yes, it is a solution to the system.
3. For $(4, -3)$: Yes, it is a solution to the system.
4. For $(-4, -6)$: No, it is not a solution to the system.