Question

oscar started doing sit - ups to prepare for the school fitness test. on 5 days he did: 84 sit - ups 86 sit - ups 14 sit - ups 57 sit - ups 28 sit - ups. what was the mean absolute deviation of the numbers of sit - ups he did? if the answer is a decimal, round it to the nearest tenth. mean absolute deviation (mad): sit - ups

Explanation:

Step1: Calculate the mean

First, find the sum of the numbers: $84 + 86+14 + 57+28=269$. Then divide by the number of data - points ($n = 5$). The mean $\bar{x}=\frac{269}{5}=53.8$.

Step2: Calculate the absolute deviations

Find the absolute difference between each data - point and the mean:
$|84 - 53.8|=30.2$, $|86 - 53.8|=32.2$, $|14 - 53.8|=39.8$, $|57 - 53.8|=3.2$, $|28 - 53.8|=25.8$.

Step3: Calculate the mean of the absolute deviations

Find the sum of the absolute deviations: $30.2+32.2 + 39.8+3.2+25.8 = 131.2$. Then divide by the number of data - points ($n = 5$). The mean absolute deviation $MAD=\frac{131.2}{5}=26.24$.

Step4: Round to the nearest tenth

Rounding $26.24$ to the nearest tenth gives $26.2$.

Answer:

$26.2$