Question

over a 90 - day growing season, how many total hours of sunlight does each location receive?
despite the whole of pumpkins being edible we typically consume only 70 percent of a pumpkin. how many kilograms of an average alaskan pumpkin would you expect to be eaten based on this? (1 pound =.45 kg)
pumpkins can be fermented, a process where the plants consume their sugar without the presence of oxygen. a fermenting pumpkin has an initial glucose mass of 7.7 kilograms and after fermenting for 2 weeks has a final glucose mass of 2.4 kilograms.
what percentage of the pumpkin was fermented?
what is the rate of glucose fermented in grams/hour?

Explanation:

Step1: Calculate total sunlight hours for Alaska

Alaska has 20 hours of daylight per day. Multiply by 90 - day growing - season.
$20\times90 = 1800$ hours

Step2: Calculate total sunlight hours for Hawaii

Hawaii has 13 hours of daylight per day. Multiply by 90 - day growing - season.
$13\times90=1170$ hours

Step3: Calculate amount of Alaskan pumpkin eaten

An average Alaskan pumpkin is not given in pounds. Let's assume it's the same as the typical Hawaiian pumpkin which is 20 pounds. First convert pounds to kilograms: $20\times0.45 = 9$ kg. Then find 70% of it.
$9\times0.7=6.3$ kg

Step4: Calculate percentage of pumpkin fermented

The amount of glucose fermented is $7.7 - 2.4=5.3$ kg. The percentage of fermentation is $\frac{5.3}{7.7}\times100\%\approx68.83\%$

Step5: Calculate rate of glucose fermented in grams/hour

First, convert the mass of glucose fermented to grams: $5.3\times1000 = 5300$ g. There are $2\times7\times24 = 336$ hours in 2 weeks. The rate is $\frac{5300}{336}\approx15.77$ g/hour

Answer:

Total sunlight hours for Alaska: 1800 hours
Total sunlight hours for Hawaii: 1170 hours
Kilograms of Alaskan pumpkin eaten: 6.3 kg
Percentage of pumpkin fermented: approximately 68.83%
Rate of glucose fermented: approximately 15.77 g/hour