Question

pa: solving one - step equations

1. is - 6 a solution to the equation: $\frac{2}{3}x=-12$? show work to justify your answer.

solve the following equations.

1. $-3 + g=-8$
2. $h - 1\frac{2}{3}=5\frac{1}{2}$

Explanation:

Step1: Check if -6 is a solution for $\frac{2}{3}x=-12$

Substitute $x = - 6$ into the equation: $\frac{2}{3}\times(-6)=-4
eq - 12$. So -6 is not a solution.

Step2: Solve $-3 + g=-8$

Add 3 to both sides. $g=-8 + 3=-5$.

Step3: Solve $h-1\frac{2}{3}=5\frac{1}{2}$

Rewrite the mixed - numbers as improper fractions: $h-\frac{5}{3}=\frac{11}{2}$. Add $\frac{5}{3}$ to both sides. $h=\frac{11}{2}+\frac{5}{3}=\frac{33 + 10}{6}=\frac{43}{6}=7\frac{1}{6}=6\frac{5}{6}$.

Answer:

1. No.
2. $g=- 5$
3. $h = 6\frac{5}{6}$