Question

paola spent $18 to purchase a ride-all-day pass for the amusement park and to play 8 games. after playing a total of 20 games, she realized she’d spent $24.

Explanation:

Assuming the problem is to find the cost of the ride - all - day pass and the cost per game, we can solve it as follows:

Step 1: Define variables

Let $p$ be the cost of the ride - all - day pass (in dollars) and $g$ be the cost per game (in dollars).

From the first situation, we have the equation: $p + 8g=18$ (because Paola spent $18$ dollars on the pass and 8 games).

From the second situation, we have the equation: $p + 20g = 24$ (because Paola spent $24$ dollars on the pass and 20 games).

Step 2: Subtract the first equation from the second

Subtract the equation $p + 8g=18$ from $p + 20g=24$.

$(p + 20g)-(p + 8g)=24 - 18$

Simplify the left - hand side: $p+20g - p - 8g=12g$

Simplify the right - hand side: $6$

So, $12g=6$

Step 3: Solve for g

Divide both sides of the equation $12g = 6$ by 12:

$g=\frac{6}{12}=\frac{1}{2}=0.5$

Step 4: Solve for p

Substitute $g = 0.5$ into the first equation $p+8g = 18$

$p+8\times0.5=18$

$p + 4=18$

Subtract 4 from both sides: $p=18 - 4=14$

Answer:

The cost of the ride - all - day pass is $\$14$ and the cost per game is $\$0.5$ (or 50 cents).

If the problem was something else (for example, finding the cost per game or the cost of the pass), the above solution can be adjusted. Since the original problem was not fully stated, but based on the given information, this is a common problem - solving approach.