Question

parents that are heterozygous for having freckles (dominant) are crossed. which correctly describes their offspring? twenty - five percent have freckles. twenty - five percent are ft. seventy - five percent have freckles. seventy - five percent are ft.

Explanation:

Step1: Define alleles

Let F represent the dominant allele for freckles and f represent the recessive allele. Heterozygous parents have the genotype Ff.

Step2: Set up Punnett - square

The possible gametes from each parent are F and f. The Punnett - square has 4 possible combinations: FF, Ff, Ff, ff.

Step3: Analyze genotypes and phenotypes

FF and Ff genotypes result in the freckled phenotype (dominant). There are 3 out of 4 combinations (FF, Ff, Ff) that result in freckles. $\frac{3}{4}= 75\%$.

Answer:

Seventy - five percent have freckles.