Question

part 2 of 2
19.0 g of $\text{nahco}_3$ in 480. ml of solution. be sure your answer has the correct number of significant figures.
$\boldsymbol{square}$ m $\text{nahco}_3$

Explanation:

Step1: Calculate molar mass of $\text{NaHCO}_3$

Molar mass = $23.0 + 1.0 + 12.0 + 3\times16.0 = 84.0\ \text{g/mol}$

Step2: Convert mass to moles

$n = \frac{m}{M} = \frac{19.0\ \text{g}}{84.0\ \text{g/mol}} \approx 0.2262\ \text{mol}$

Step3: Convert volume to liters

$V = 480.\ \text{mL} = \frac{480.}{1000} = 0.480\ \text{L}$

Step4: Calculate molarity

$M = \frac{n}{V} = \frac{0.2262\ \text{mol}}{0.480\ \text{L}} \approx 0.471\ \text{mol/L}$

Answer:

$0.471\ \text{M NaHCO}_3$