QUESTION IMAGE
Question
part 1 - a bunch of systems
solve each system of equations without graphing and show your reasoning. then, check your solutions.
a. $2x + 3y = 7$
$-2x + 4y = 14$
b. $2x + 3y = 7$
$3x - 3y = 3$
c. $2x + 3y = 5$
$2x + 4y = 9$
d. $2x + 3y = 16$
$6x - 5y = 20$
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a. System 1
Step1: Add equations to eliminate $x$
Step2: Solve for $y$
$y = \frac{21}{7} = 3$
Step3: Substitute $y=3$ into first equation
$2x + 3(3) = 7$
$2x + 9 = 7$
Step4: Solve for $x$
$2x = 7 - 9 = -2$
$x = \frac{-2}{2} = -1$
Step5: Verify solution
Substitute $x=-1, y=3$ into second equation:
$-2(-1) + 4(3) = 2 + 12 = 14$, which matches.
b. System 2
Step1: Add equations to eliminate $y$
Step2: Solve for $x$
$x = \frac{10}{5} = 2$
Step3: Substitute $x=2$ into first equation
$2(2) + 3y = 7$
$4 + 3y = 7$
Step4: Solve for $y$
$3y = 7 - 4 = 3$
$y = \frac{3}{3} = 1$
Step5: Verify solution
Substitute $x=2, y=1$ into second equation:
$3(2) - 3(1) = 6 - 3 = 3$, which matches.
c. System 3
Step1: Subtract first equation from second to eliminate $x$
Step2: Substitute $y=4$ into first equation
$2x + 3(4) = 5$
$2x + 12 = 5$
Step3: Solve for $x$
$2x = 5 - 12 = -7$
$x = \frac{-7}{2} = -3.5$
Step4: Verify solution
Substitute $x=-3.5, y=4$ into second equation:
$2(-3.5) + 4(4) = -7 + 16 = 9$, which matches.
d. System 4
Step1: Multiply first equation by 3 to align $x$ terms
$3(2x + 3y) = 3(16)$
$6x + 9y = 48$
Step2: Subtract second equation from new equation
Step3: Solve for $y$
$y = \frac{28}{14} = 2$
Step4: Substitute $y=2$ into first equation
$2x + 3(2) = 16$
$2x + 6 = 16$
Step5: Solve for $x$
$2x = 16 - 6 = 10$
$x = \frac{10}{2} = 5$
Step6: Verify solution
Substitute $x=5, y=2$ into second equation:
$6(5) - 5(2) = 30 - 10 = 20$, which matches.
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a. $x=-1$, $y=3$
b. $x=2$, $y=1$
c. $x=-3.5$, $y=4$
d. $x=5$, $y=2$