Question

1. part a complete the table to multiply (4 - 3x) and (x² - 2x + 1).

part b write the standard form of the multiplication performed in part a.

Explanation:

Step1: Multiply 4 by each term

$4 \times x^2 = 4x^2$
$4 \times (-2x) = -8x$
$4 \times 1 = 4$

Step2: Multiply $-3x$ by each term

$-3x \times x^2 = -3x^3$
$-3x \times (-2x) = 6x^2$
$-3x \times 1 = -3x$

Step3: Combine all terms

$-3x^3 + 4x^2 + 6x^2 -8x -3x + 4$

Step4: Combine like terms

$-3x^3 + (4+6)x^2 + (-8-3)x + 4 = -3x^3 + 10x^2 -11x + 4$

Answer:

Part A Table Results:

	$x^2$	$-2x$	$1$
$-3x$	$-3x^3$	$6x^2$	$-3x$

Part B Standard Form:

$-3x^3 + 10x^2 -11x + 4$