Question

part a
how strong is the electric field between two parallel plates 5.8 mm apart if the potential difference between them is 220 v?
express your answer to two significant figures and include the appropriate units.
e = value units

Explanation:

Step1: Recall the formula for electric field

The formula for the electric field $E$ between two parallel - plates is $E=\frac{V}{d}$, where $V$ is the potential difference and $d$ is the distance between the plates.

Step2: Convert the distance to SI units

The distance $d = 5.8\ mm=5.8\times10^{-3}\ m$, and $V = 220\ V$.

Step3: Calculate the electric field

Substitute the values into the formula: $E=\frac{V}{d}=\frac{220\ V}{5.8\times 10^{-3}\ m}\approx3.8\times 10^{4}\ V/m$.

Answer:

$3.8\times 10^{4}\ V/m$