Question

part of one row of the periodic table is shown. which elements atoms have the greatest average number of neutrons? 50 sn tin 118.71 51 sb antimony 121.76 52 te tellurium 127.60 53 i iodine 126.90 tin (sn) antimony (sb) tellurium (te) iodine (i)

Explanation:

Step1: Recall the formula for number of neutrons

Number of neutrons = Atomic mass - Atomic number.

Step2: Calculate neutrons for Sn

Atomic number of Sn is 50, atomic mass is 118.71. Neutrons = 118.71 - 50 = 68.71.

Step3: Calculate neutrons for Sb

Atomic number of Sb is 51, atomic mass is 121.76. Neutrons = 121.76 - 51 = 70.76.

Step4: Calculate neutrons for Te

Atomic number of Te is 52, atomic mass is 127.60. Neutrons = 127.60 - 52 = 75.60.

Step5: Calculate neutrons for I

Atomic number of I is 53, atomic mass is 126.90. Neutrons = 126.90 - 53 = 73.90.

Answer:

C. tellurium (Te)