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part: 1 / 2 part 2 of 2 factor the trinomial. $x^{2}-4x + 4=square$

Question

part: 1 / 2
part 2 of 2
factor the trinomial.
$x^{2}-4x + 4=square$

Explanation:

Step1: Identify the form

The trinomial $x^{2}-4x + 4$ is in the form of $a^{2}-2ab + b^{2}$, where $a=x$ and $b = 2$ since $a^{2}=x^{2}$, $2ab=2\times x\times2 = 4x$ and $b^{2}=4$.

Step2: Apply the perfect - square formula

The perfect - square formula is $a^{2}-2ab + b^{2}=(a - b)^{2}$. Substituting $a=x$ and $b = 2$ into the formula, we get $x^{2}-4x + 4=(x - 2)^{2}$.

Answer:

$(x - 2)^{2}$