Question

part c
pb
express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. for example, he2s^22p^2 should be entered as he2s^22p^2.
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part d
cd
express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. for example, he2s^22p^2 should be entered as he2s^22p^2.
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Explanation:

Step1: Find Pb's noble gas core

Lead (Pb) has an atomic number of 82. The preceding noble gas is Xenon (Xe, atomic number 54).

Step2: Add remaining electrons

82 - 54 = 28 electrons left. Fill orbitals by energy order: $6s^24f^{14}5d^{10}6p^2$

Step3: Combine for condensed form

Condense using Xe as the core: $[Xe]6s^24f^{14}5d^{10}6p^2$
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Step1: Find Cd's noble gas core

Cadmium (Cd) has an atomic number of 48. The preceding noble gas is Krypton (Kr, atomic number 36).

Step2: Add remaining electrons

48 - 36 = 12 electrons left. Fill orbitals by energy order: $5s^24d^{10}$

Step3: Combine for condensed form

Condense using Kr as the core: $[Kr]5s^24d^{10}$

Answer:

Part C: $[Xe]6s^24f^{14}5d^{10}6p^2$
Part D: $[Kr]5s^24d^{10}$