Question

part e write full electron configurations for cl. express your answer in complete form in the order of orbital filling as a string without blank space between orbitals. for example, 1s²2s² should be entered as 1s^22s^2. submit request answer part f complete previous part(s) part g write full electron configurations for sr. express your answer in complete form in the order of orbital filling as a string without blank space between orbitals. for example, 1s²2s² should be entered as 1s^22s^2. submit request answer

Explanation:

Step1: Find Cl's atomic number

Chlorine (Cl) has an atomic number of 17, so it has 17 electrons. Fill orbitals in order: $1s, 2s, 2p, 3s, 3p$.
$1s^22s^22p^63s^23p^5$ (format as $1s^22s^22p^63s^23p^5$)

Step2: Find Sr's atomic number

Strontium (Sr) has an atomic number of 38, so it has 38 electrons. Fill orbitals in order: $1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s$.
$1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^2$ (format as $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^2$)

Answer:

Part E: $1s^22s^22p^63s^23p^5$
Part G: $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^2$