Question

perimeter and area using the distance formula
j (-1, -1)
c (27, -20)
d = \sqrt{( )^{2}+( )^{2}}
d =

Explanation:

Step1: Identify distance - formula values

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $(x_1,y_1)=(-1,-1)$ and $(x_2,y_2)=(27,-20)$.

Step2: Calculate differences

$x_2 - x_1=27-(-1)=28$ and $y_2 - y_1=-20 - (-1)=-19$.

Step3: Substitute into formula

$d=\sqrt{(28)^2+(-19)^2}=\sqrt{784 + 361}=\sqrt{1145}\approx33.84$.

Answer:

$d=\sqrt{(28)^2+(-19)^2}\approx33.84$