Question

the perimeter of the isosceles triangle below is 48. what equation would you use to solve for x? x + 22 10 a. x + 22+10 = 48 b. x + 22 - 10 = 48 c. x + 22 + x + 22+10 = 48 d. x + 22 + x + 22 + x + 22 = 10

Explanation:

Step1: Recall perimeter formula

The perimeter $P$ of a triangle is the sum of the lengths of its sides. For an isosceles triangle with two equal - length sides of length $x + 22$ and a base of length 10, and given $P=48$.

Step2: Write the equation

The equation for the perimeter is $(x + 22)+(x + 22)+10=48$, which simplifies to $x + 22+x + 22+10 = 48$.

Answer:

C. $x + 22+x + 22+10 = 48$