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4. the perimeter of the triangle at right is 100 sq. cm. write an equat…

Question

  1. the perimeter of the triangle at right is 100 sq. cm. write an equation and solve for x.

Explanation:

Step1: Set up the perimeter - equation

The perimeter of a triangle is the sum of the lengths of its sides. So, $x+(x + 5)+(2x+1)=100$.

Step2: Combine like - terms

Combining the $x$ terms on the left - hand side gives $(x+x + 2x)+(5 + 1)=100$, which simplifies to $4x+6 = 100$.

Step3: Isolate the variable term

Subtract 6 from both sides of the equation: $4x+6-6=100 - 6$, resulting in $4x=94$.

Step4: Solve for x

Divide both sides of the equation by 4: $x=\frac{94}{4}=\frac{47}{2}=23.5$.

Answer:

$x = 23.5$