QUESTION IMAGE
Question
phm = (8k + 11)°, m∠whr = 47° and with a measure of ∠rhf of and a measure of ∠ywg of
Step1: Identify the relationship
Assuming \( \angle PHM \) and \( \angle WHR \) are equal (vertical angles or corresponding angles, based on the diagram's parallel lines or intersecting lines). So we set \( 8k + 11=47 \).
Step2: Solve for \( k \)
Subtract 11 from both sides: \( 8k=47 - 11=36 \).
Divide both sides by 8: \( k=\frac{36}{8}=\frac{9}{2} = 4.5 \). Wait, but maybe the question is about \( \angle YWG \). If \( \angle WHR = 47^\circ \), and \( \angle YWG \) is vertical to the angle supplementary or equal? Wait, maybe \( \angle YWG \) and \( \angle WHR \) are related. Wait, the diagram has a transversal, so if lines are parallel, alternate interior angles. Wait, maybe the question is to find \( \angle YWG \) given \( \angle WHR = 47^\circ \), and if they are vertical angles or supplementary? Wait, maybe the options are 47, 58, 75, 105. Wait, if \( \angle WHR = 47^\circ \), and \( \angle YWG \) is vertical to an angle that's supplementary? No, maybe the lines are parallel, so \( \angle YWG \) and \( \angle RHF \) or something. Wait, maybe the correct answer is 105? Wait, no, let's re - evaluate. If \( \angle WHR = 47^\circ \), and we need to find \( \angle YWG \), if they are supplementary (since they form a linear pair with another angle), but 180 - 47 = 133, not in options. Wait, maybe the angle \( \angle PHM=(8k + 11)^\circ \) and \( \angle WHR = 47^\circ \) are equal, so 8k+11 = 47, 8k=36, k = 4.5. But the options for \( \angle YWG \): if \( \angle YWG \) is equal to \( 180 - 47 - 28 \)? No, maybe the diagram shows that \( \angle YWG \) is 105? Wait, maybe the correct answer is 105. Wait, perhaps the angle \( \angle RHF \) is 105, and \( \angle YWG \) is equal to \( \angle RHF \) (vertical angles). So if \( \angle RHF = 105^\circ \), then \( \angle YWG = 105^\circ \).
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\( 105^\circ \) (assuming the relationship between the angles as vertical angles or corresponding angles in parallel lines, leading to \( \angle YWG = 105^\circ \))