Question

a picture that is 21 in. long and 10 in. wide is going to be reduced to fit in a space of 6 in. long. what will the reduced width be? the reduced width will be \boxed{} in. (round to the nearest hundredths place)

Explanation:

Step1: Set up proportion equation

Let $w$ = reduced width.
$\frac{\text{Original length}}{\text{Reduced length}} = \frac{\text{Original width}}{\text{Reduced width}}$
$\frac{21}{6} = \frac{10}{w}$

Step2: Cross-multiply to solve for $w$

$21w = 6 \times 10$
$21w = 60$

Step3: Isolate $w$ and calculate

$w = \frac{60}{21}$
$w \approx 2.857$

Step4: Round to nearest hundredth

Round 2.857 to two decimal places.

Answer:

2.86