Question

1. a piece of lead metal had a mass of 217.90 grams. bob determined the volume by water displacement. the volume of water was 30.6 ml. the volume of water and lead was 49.8 ml. calculate the density of the lead. d = \\(\frac{m}{v}\\) 7. what is the volume, in centimeters cubed, of a block of steel (density of steel 7.85 g/cm³), which has a mass of 49.6 grams?

Explanation:

Step1: Calculate the volume of lead

The volume of lead $V$ is the volume of water and lead minus the volume of water.
$V = 49.8 - 30.6=19.2$ mL. Since 1 mL = 1 $cm^{3}$, $V = 19.2$ $cm^{3}$.

Step2: Calculate the density of lead

The density formula is $D=\frac{m}{V}$, where $m = 217.90$ g and $V = 19.2$ $cm^{3}$.
$D=\frac{217.90}{19.2}\approx11.35$ g/$cm^{3}$

Step3: Calculate the volume of steel

For the steel block, using the density formula $D=\frac{m}{V}$, we can re - arrange it to $V=\frac{m}{D}$. Given $m = 49.6$ g and $D = 7.85$ g/$cm^{3}$.
$V=\frac{49.6}{7.85}\approx6.32$ $cm^{3}$

Answer:

The density of the lead is approximately 11.35 g/$cm^{3}$ and the volume of the steel block is approximately 6.32 $cm^{3}$