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Question
a pilot flies 720 miles from dallas, texas, to his first destination. after dropping off his cargo, he flies southeast 290 miles to his second destination. if the angle formed by his trip is 125°, what is the distance he will fly from the second destination back to dallas? 490 miles 918 miles 1,010 miles 842,026 miles
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Using the Law of Cosines \(c^{2}=a^{2}+b^{2}-2ab\cos C\), where \(a = 720\), \(b = 290\), and \(C=125^{\circ}\).
\(c=\sqrt{720^{2}+290^{2}-2\times720\times290\times\cos(125^{\circ})}\approx918\) miles
B. 918 miles