Question

place each noble gas symbol in front of the appropriate partial electron configuration to create an accurate electron configuration.
periodic table image: 1 h, 2 he; 3 li, 4 be; 5 b, 6 c, 7 n, 8 o, 9 f, 10 ne; 11 na, 12 mg; 13 al, 14 si, 15 p, 16 s, 17 cl, 18 ar; 19 k, 20 ca; 21 sc, 22 ti, 23 v, 24 cr, 25 mn, 26 fe, 27 co, 28 ni, 29 cu, 30 zn; 31 ga, 32 ge, 33 as, 34 se, 35 br, 36 kr; 37 rb, 38 sr; 39 y, 40 zr, 41 nb, 42 mo, 43 tc, 44 ru, 45 rh, 46 pd, 47 ag, 48 cd; 49 in, 50 sn, 51 sb, 52 te, 53 i, 54 xe; 55 cs, 56 ba; 57 la, 58 ce, 59 pr, 60 nd, 61 pm, 62 sm, 63 eu, 64 gd, 65 tb, 66 dy, 67 ho, 68 er, 69 tm, 70 yb, 71 lu; 72 hf, 73 ta, 74 w, 75 re, 76 os, 77 ir, 78 pt, 79 au, 80 hg; 81 tl, 82 pb, 83 bi, 84 po, 85 at, 86 rn; 87 fr, 88 ra; 89 ac, 90 th, 91 pa, 92 u, 93 np, 94 pu, 95 am, 96 cm, 97 bk, 98 cf, 99 es, 100 fm, 101 md, 102 no, 103 lr
noble gas symbols: he, ne, ar, kr, xe
partial electron configurations: (4s^2 3d^{10} 4p^2); (5s^2 4d^{10} 5p^5); (2s^2 2p^5); (6s^2 4f^{14} 5d^{10} 6p^2); (3s^2)

Explanation:

To solve this, we match each partial electron configuration with the appropriate noble gas (its core electron configuration) by considering the electron configuration rules and noble gas electron configurations:

Step 1: Analyze \( 4s^2 3d^{10} 4p^2 \)

The noble gas before the 4th period (where this configuration lies) is Ar (\([Ar] = 1s^2 2s^2 2p^6 3s^2 3p^6\)). The partial configuration \( 4s^2 3d^{10} 4p^2 \) starts after Ar’s configuration. So:
\([Ar] 4s^2 3d^{10} 4p^2\)

Step 2: Analyze \( 5s^2 4d^{10} 5p^5 \)

The noble gas before the 5th period is Kr (\([Kr] = [Ar] 4s^2 3d^{10} 4p^6\)). The partial configuration \( 5s^2 4d^{10} 5p^5 \) starts after Kr’s configuration. Wait, no—wait, the noble gas symbols given are [He], [Ne], [Ar], [Kr], [Xe]. Wait, the partial \( 5s^2 4d^{10} 5p^5 \): the noble gas core here is Kr? Wait, no, the given noble gas symbols include [Kr]? Wait, the problem’s noble gas symbols are [He], [Ne], [Ar], [Kr], [Xe]. Let’s check the period: 5th period. The noble gas before 5th period is Kr (\([Kr] = [Ar] 4s^2 3d^{10} 4p^6\)). So \( 5s^2 4d^{10} 5p^5 \) is after Kr, so:
\([Kr] 5s^2 4d^{10} 5p^5\)

Step 3: Analyze \( 2s^2 2p^5 \)

The noble gas before the 2nd period is He (\([He] = 1s^2\)). The partial configuration \( 2s^2 2p^5 \) starts after He’s configuration. So:
\([He] 2s^2 2p^5\)

Step 4: Analyze \( 6s^2 4f^{14} 5d^{10} 6p^2 \)

The noble gas before the 6th period (for elements with f-orbitals) is Xe (\([Xe] = [Kr] 5s^2 4d^{10} 5p^6\)). The partial configuration \( 6s^2 4f^{14} 5d^{10} 6p^2 \) starts after Xe’s configuration. So:
\([Xe] 6s^2 4f^{14} 5d^{10} 6p^2\)

Step 5: Analyze \( 3s^2 \)

The noble gas before the 3rd period is Ne (\([Ne] = 1s^2 2s^2 2p^6\)). The partial configuration \( 3s^2 \) starts after Ne’s configuration. So:
\([Ne] 3s^2\)

Final Matches:

• \( 4s^2 3d^{10} 4p^2 \): \(\boldsymbol{[Ar]}\)
• \( 5s^2 4d^{10} 5p^5 \): \(\boldsymbol{[Kr]}\)
• \( 2s^2 2p^5 \): \(\boldsymbol{[He]}\)
• \( 6s^2 4f^{14} 5d^{10} 6p^2 \): \(\boldsymbol{[Xe]}\)
• \( 3s^2 \): \(\boldsymbol{[Ne]}\)

(If you need to place each noble gas symbol in the table, the matches are:

• \( 4s^2 3d^{10} 4p^2 \): [Ar]
• \( 5s^2 4d^{10} 5p^5 \): [Kr]
• \( 2s^2 2p^5 \): [He]
• \( 6s^2 4f^{14} 5d^{10} 6p^2 \): [Xe]
• \( 3s^2 \): [Ne] )

Answer:

To solve this, we match each partial electron configuration with the appropriate noble gas (its core electron configuration) by considering the electron configuration rules and noble gas electron configurations:

Step 1: Analyze \( 4s^2 3d^{10} 4p^2 \)

The noble gas before the 4th period (where this configuration lies) is Ar (\([Ar] = 1s^2 2s^2 2p^6 3s^2 3p^6\)). The partial configuration \( 4s^2 3d^{10} 4p^2 \) starts after Ar’s configuration. So:
\([Ar] 4s^2 3d^{10} 4p^2\)

Step 2: Analyze \( 5s^2 4d^{10} 5p^5 \)

The noble gas before the 5th period is Kr (\([Kr] = [Ar] 4s^2 3d^{10} 4p^6\)). The partial configuration \( 5s^2 4d^{10} 5p^5 \) starts after Kr’s configuration. Wait, no—wait, the noble gas symbols given are [He], [Ne], [Ar], [Kr], [Xe]. Wait, the partial \( 5s^2 4d^{10} 5p^5 \): the noble gas core here is Kr? Wait, no, the given noble gas symbols include [Kr]? Wait, the problem’s noble gas symbols are [He], [Ne], [Ar], [Kr], [Xe]. Let’s check the period: 5th period. The noble gas before 5th period is Kr (\([Kr] = [Ar] 4s^2 3d^{10} 4p^6\)). So \( 5s^2 4d^{10} 5p^5 \) is after Kr, so:
\([Kr] 5s^2 4d^{10} 5p^5\)

Step 3: Analyze \( 2s^2 2p^5 \)

The noble gas before the 2nd period is He (\([He] = 1s^2\)). The partial configuration \( 2s^2 2p^5 \) starts after He’s configuration. So:
\([He] 2s^2 2p^5\)

Step 4: Analyze \( 6s^2 4f^{14} 5d^{10} 6p^2 \)

The noble gas before the 6th period (for elements with f-orbitals) is Xe (\([Xe] = [Kr] 5s^2 4d^{10} 5p^6\)). The partial configuration \( 6s^2 4f^{14} 5d^{10} 6p^2 \) starts after Xe’s configuration. So:
\([Xe] 6s^2 4f^{14} 5d^{10} 6p^2\)

Step 5: Analyze \( 3s^2 \)

The noble gas before the 3rd period is Ne (\([Ne] = 1s^2 2s^2 2p^6\)). The partial configuration \( 3s^2 \) starts after Ne’s configuration. So:
\([Ne] 3s^2\)

Final Matches:

• \( 4s^2 3d^{10} 4p^2 \): \(\boldsymbol{[Ar]}\)
• \( 5s^2 4d^{10} 5p^5 \): \(\boldsymbol{[Kr]}\)
• \( 2s^2 2p^5 \): \(\boldsymbol{[He]}\)
• \( 6s^2 4f^{14} 5d^{10} 6p^2 \): \(\boldsymbol{[Xe]}\)
• \( 3s^2 \): \(\boldsymbol{[Ne]}\)

(If you need to place each noble gas symbol in the table, the matches are:

• \( 4s^2 3d^{10} 4p^2 \): [Ar]
• \( 5s^2 4d^{10} 5p^5 \): [Kr]
• \( 2s^2 2p^5 \): [He]
• \( 6s^2 4f^{14} 5d^{10} 6p^2 \): [Xe]
• \( 3s^2 \): [Ne] )