QUESTION IMAGE
Question
please fill out the blank spaces in the table. please show your work and staple it to the back of your paper. if you do not include your work then you will only receive partial credit. remember: a + g + c + t = 100.0% and a = t and g = c
| organism | % adenine (a) | % guanine (g) | % cytosine (c) | % thymine (t) |
|---|---|---|---|---|
| octopus | 33.2 | 23.2 | 22.0 | 31.6 |
| chicken | 22.0 | 21.6 | ||
| rat | 28.6 | 21.4 | 21.4 | 28.6 |
| streptococcus | 20.5 | 18.0 |
Step1: Recall base - pairing rules
According to Chargaff's rules, in DNA, $A = T$ and $G = C$, and $A+G + C+T=100\%$.
Step2: Calculate for Maize
Given $A = 26.8\%$, then $T=26.8\%$ (since $A = T$). Given $G = 22.8\%$, then $C = 22.8\%$ (since $G = C$).
Step3: Calculate for Octopus
Given $A = 33.2\%$, then $T = 33.2\%$ (since $A = T$). Since $A+G + C+T = 100\%$, and $A = 33.2\%$, $T = 33.2\%$, then $G + C=100-(33.2 + 33.2)=33.6\%$. Since $G = C$, $G=\frac{33.6}{2}=16.8\%$ and $C = 16.8\%$.
Step4: Calculate for Chicken
Given $G = 22.0\%$, then $C = 22.0\%$ (since $G = C$). Since $A+G + C+T = 100\%$, then $A+T=100-(22.0 + 22.0)=56\%$. Since $A = T$, $A=\frac{56}{2}=28.0\%$ and $T = 28.0\%$.
Step5: Calculate for Rat
Given $A = 28.6\%$, then $T = 28.6\%$ (since $A = T$). Given $G = 21.4\%$, then $C = 21.4\%$ (since $G = C$).
Step6: Calculate for Streptococcus
Given $G = 20.5\%$, then $C = 20.5\%$ (since $G = C$). Then $A+T=100-(20.5 + 20.5)=59\%$. Since $A = T$, $A=\frac{59}{2}=29.5\%$ and $T = 29.5\%$.
| Organism | % Adenine (A) | % Guanine (G) | % Cytosine (C) | % Thymine (T) |
|---|---|---|---|---|
| Octopus | 33.2 | 16.8 | 16.8 | 33.2 |
| Chicken | 28.0 | 22.0 | 22.0 | 28.0 |
| Rat | 28.6 | 21.4 | 21.4 | 28.6 |
| Streptococcus | 29.5 | 20.5 | 20.5 | 29.5 |
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Step1: Recall base - pairing rules
According to Chargaff's rules, in DNA, $A = T$ and $G = C$, and $A+G + C+T=100\%$.
Step2: Calculate for Maize
Given $A = 26.8\%$, then $T=26.8\%$ (since $A = T$). Given $G = 22.8\%$, then $C = 22.8\%$ (since $G = C$).
Step3: Calculate for Octopus
Given $A = 33.2\%$, then $T = 33.2\%$ (since $A = T$). Since $A+G + C+T = 100\%$, and $A = 33.2\%$, $T = 33.2\%$, then $G + C=100-(33.2 + 33.2)=33.6\%$. Since $G = C$, $G=\frac{33.6}{2}=16.8\%$ and $C = 16.8\%$.
Step4: Calculate for Chicken
Given $G = 22.0\%$, then $C = 22.0\%$ (since $G = C$). Since $A+G + C+T = 100\%$, then $A+T=100-(22.0 + 22.0)=56\%$. Since $A = T$, $A=\frac{56}{2}=28.0\%$ and $T = 28.0\%$.
Step5: Calculate for Rat
Given $A = 28.6\%$, then $T = 28.6\%$ (since $A = T$). Given $G = 21.4\%$, then $C = 21.4\%$ (since $G = C$).
Step6: Calculate for Streptococcus
Given $G = 20.5\%$, then $C = 20.5\%$ (since $G = C$). Then $A+T=100-(20.5 + 20.5)=59\%$. Since $A = T$, $A=\frac{59}{2}=29.5\%$ and $T = 29.5\%$.
| Organism | % Adenine (A) | % Guanine (G) | % Cytosine (C) | % Thymine (T) |
|---|---|---|---|---|
| Octopus | 33.2 | 16.8 | 16.8 | 33.2 |
| Chicken | 28.0 | 22.0 | 22.0 | 28.0 |
| Rat | 28.6 | 21.4 | 21.4 | 28.6 |
| Streptococcus | 29.5 | 20.5 | 20.5 | 29.5 |