Question

pm is the perpendicular bisector of xy, and px = 8. which statement below can be proved?

Explanation:

Step1: Recall property of perpendicular bisector

Any point on the perpendicular bisector of a line - segment is equidistant from the endpoints of the line - segment. Since $\overline{PM}$ is the perpendicular bisector of $\overline{XY}$ and $P$ is a point on $\overline{PM}$, and $PX = 8$.

Step2: Apply the equidistant property

We know that $PX=PY$. Given $PX = 8$, then $PY = 8$.

Answer:

$PY = 8$