Question

point $p$ is the image of $p(6,0)$ under the translation $(x,y)\to(x - 6,y - 1)$. what are the coordinates of $p$?

Explanation:

Step1: Identify the x - coordinate formula

For the x - coordinate of the image, use $x'=x - 6$. Given $x = 6$, then $x'=6-6$.
$x'=0$

Step2: Identify the y - coordinate formula

For the y - coordinate of the image, use $y'=y - 1$. Given $y = 0$, then $y'=0 - 1$.
$y'=-1$

Answer:

$(0,-1)$