Question

point $p$ is the image of $p(6,0)$ under the translation $(x,y)\to(x - 6,y - 1)$. what are the coordinates of $p$? ( , )

Explanation:

Step1: Find x - coordinate of P'

Given \(x = 6\) in the translation \((x,y)\to(x - 6,y - 1)\), substitute \(x = 6\) into \(x-6\). So \(x'=6 - 6=0\).

Step2: Find y - coordinate of P'

Given \(y = 0\) in the translation \((x,y)\to(x - 6,y - 1)\), substitute \(y = 0\) into \(y - 1\). So \(y'=0 - 1=-1\).

Answer:

\((0,-1)\)