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Question
point h is the mid - point of side fk. for the triangles to be congruent by sss, what must be the value of x? 3x - 2 2x + 4 1 6 3 8
Step1: Set equal sides for SSS congruence
Since the triangles are congruent by SSS (Side - Side - Side) and we assume the corresponding sides are equal, we set up the equation \(3x - 2=2x + 4\).
Step2: Solve the equation for \(x\)
Subtract \(2x\) from both sides: \(3x-2x - 2=2x-2x + 4\), which simplifies to \(x-2 = 4\). Then add 2 to both sides: \(x=4 + 2\).
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\(x = 6\)