Question

point h is the midpoint of side fk. for the triangles to be congruent by sss, what must be the value of x? 3x - 2, 2x + 4 options: 1, 3, 6, 8

Explanation:

Step1: Set equal congruent sides

Since \(H\) is the midpoint, \(FH = HK\), and for SSS congruence, \(FG = JK\), so:
\(3x - 2 = 2x + 4\)

Step2: Isolate \(x\) variable

Subtract \(2x\) from both sides:
\(3x - 2x - 2 = 4\)

Step3: Solve for \(x\)

Add 2 to both sides:
\(x = 4 + 2\)

Answer:

C. 6