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Question
point h is the midpoint of side fk. for the triangles to be congruent by sss, what must be the value of x? 8 6 3 1
Step1: Set equal side - lengths for SSS congruence
Since for the triangles to be congruent by SSS, the corresponding sides must be equal. We set \(3x - 2=2x + 4\).
Step2: Solve the equation for \(x\)
Subtract \(2x\) from both sides of the equation \(3x - 2=2x + 4\). We get \(3x-2x-2=2x - 2x+4\), which simplifies to \(x-2 = 4\). Then add 2 to both sides: \(x-2 + 2=4 + 2\), so \(x=6\).
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