Question

b. point c is translated 3 units to the left and 2 units up. plot this point on the grid and label it c. select point from the choices above the coordinate plane. click on any intersection on the plane to make a point. click a point and type your label in the box. press enter.

Explanation:

To solve the translation of point \( C \) (assuming original coordinates, say \( (x,y) \)):

Step 1: Understand Translation Rules

Translating 3 units left: subtract 3 from the \( x \)-coordinate (\( x - 3 \)).
Translating 2 units up: add 2 to the \( y \)-coordinate (\( y + 2 \)).

Step 2: Apply to Original Point (Example: If \( C \) is at \( (a,b) \))

New \( x \)-coordinate: \( a - 3 \)
New \( y \)-coordinate: \( b + 2 \)

Step 3: Plot the New Point

Locate \( (a - 3, b + 2) \) on the coordinate plane and label it \( C' \).

(Note: If the original coordinates of \( C \) were provided, substitute them into the formula. For example, if \( C = (5, 3) \), then \( C' = (5 - 3, 3 + 2) = (2, 5) \), and plot \( (2, 5) \).)

To finalize, identify \( C \)’s original coordinates, apply the translation, and plot \( C' \) at \( (x - 3, y + 2) \).

Answer:

To solve the translation of point \( C \) (assuming original coordinates, say \( (x,y) \)):

Step 1: Understand Translation Rules

Translating 3 units left: subtract 3 from the \( x \)-coordinate (\( x - 3 \)).
Translating 2 units up: add 2 to the \( y \)-coordinate (\( y + 2 \)).

Step 2: Apply to Original Point (Example: If \( C \) is at \( (a,b) \))

New \( x \)-coordinate: \( a - 3 \)
New \( y \)-coordinate: \( b + 2 \)

Step 3: Plot the New Point

Locate \( (a - 3, b + 2) \) on the coordinate plane and label it \( C' \).

(Note: If the original coordinates of \( C \) were provided, substitute them into the formula. For example, if \( C = (5, 3) \), then \( C' = (5 - 3, 3 + 2) = (2, 5) \), and plot \( (2, 5) \).)

To finalize, identify \( C \)’s original coordinates, apply the translation, and plot \( C' \) at \( (x - 3, y + 2) \).