Question

1. (2 points) eight ounces of a hard liquor (such as whiskey) typically contain about 70 grams of alcohol. consider a 180 - pound man, with approximately 6000 milliliters of blood, who quickly drinks 8 ounces of hard liquor. if the man’s body eliminates the alcohol (through metabolism) at a rate of 15 grams per hour, then what is his blood alcohol content 4.2 hours after drinking the liquor? express your answer in units of grams per hundred milliliters.

Explanation:

Step1: Calculate initial alcohol amount

Initial alcohol = 70 grams

Step2: Calculate metabolized alcohol in 4.2h

Metabolized alcohol = $15 \times 4.2 = 63$ grams

Step3: Find remaining alcohol

Remaining alcohol = $70 - 63 = 7$ grams

Step4: Calculate blood alcohol concentration

Concentration = $\frac{\text{Remaining alcohol}}{\text{Total blood volume}} \times 100$
$\text{Concentration} = \frac{7}{6000} \times 100 = \frac{700}{6000} = \frac{7}{60} \approx 0.117$ grams per hundred milliliters

Answer:

Approximately 0.12 grams per hundred milliliters (or exactly $\frac{7}{60}$ grams per hundred milliliters)