Question

the polynomial $-16t^2 + vt + h_0$ models the height, in feet, of a ball $t$ seconds after it is thrown. in this polynomial, $v$ represents the initial vertical velocity of the ball and $h_0$ represents the initial height of the ball.

min throws a baseball from a height of 6 feet with an initial vertical velocity of 30 feet per second. which polynomial models the height of the ball, in feet?

$14t^2 + 6$
$-16t^2 + 36t$
$-16t^2 + 6t + 30$
$-16t^2 + 30t + 6$

Explanation:

Step1: Identify given values

We know the height model is $-16t^2 + vt + h_0$, where $v$ is initial vertical velocity and $h_0$ is initial height. Given $v = 30$ (ft/s) and $h_0 = 6$ (ft).

Step2: Substitute values into the model

Substitute $v = 30$ and $h_0 = 6$ into $-16t^2 + vt + h_0$. So we get $-16t^2 + 30t + 6$.

Answer:

$-16t^2 + 30t + 6$