Question

the population of bacteria in an experiment increases by 73% every 2 days. if there were 150 bacteria microorganisms at the beginning, how many would there be after 8 days? future amount = 150(1 + ?) future amount = i(1 + r)^t enter the number that belongs in the green box.

Explanation:

Step1: Determine the number of 2 - day periods

The time - frame is 8 days and the growth period is 2 days. So, the number of 2 - day periods $n=\frac{8}{2}=4$.

Step2: Identify the growth rate

The growth rate $r = 73\%=0.73$.

Step3: Analyze the formula

The formula for future amount is $A = I(1 + r)^t$, where $I$ is the initial amount, $r$ is the growth rate per period, and $t$ is the number of periods. In the given formula $Future\ Amount=150(1 + [?])$, we need to find the value inside the brackets for one 2 - day growth period. The value inside the brackets is the growth rate for a single 2 - day period.

Answer:

$0.73$