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the population of bacteria in an experiment increases by 84% every 2 da…

Question

the population of bacteria in an experiment increases by 84% every 2 days. if there were 75 bacteria microorganisms at the beginning, how many would there be after 20 days?
future amount = 75(1 + ?)^
future amount = i(1 + r)^t
enter the number that belongs in the green box.

Explanation:

Step1: Identify the growth - rate per 2 - day period

The population increases by 84% every 2 days. To use the formula $Future\ Amount = I(1 + r)^t$, we need to convert the percentage to a decimal. 84% as a decimal is 0.84. So, $r = 0.84$.

Step2: Determine the number of 2 - day periods in 20 days

The time period is 20 days and the growth occurs every 2 days. So, the number of 2 - day periods $t=\frac{20}{2}=10$.

Answer:

0.84