Question

(b) problem 11: (first taught in lesson 30)
find the measures of the angles of an isosceles triangle with a vertex angle of 50°.
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Explanation:

Step1: Recall angle - sum property

The sum of interior angles of a triangle is $180^{\circ}$. In an isosceles triangle, two angles are equal.

Step2: Let the equal angles be $x$

We know one angle is $50^{\circ}$. So, $50 + 2x=180$.

Step3: Solve for $x$

Subtract 50 from both sides: $2x = 180 - 50=130$. Then divide by 2: $x=\frac{130}{2}=65^{\circ}$. So the angles are $50^{\circ},65^{\circ},65^{\circ}$.

Answer:

$50^{\circ},65^{\circ},65^{\circ}$