Question

problem 23 of 27
what is the frequency, in s⁻¹, of a photon if the energy is 7.07×10⁻¹⁹ j? (h = 6.626×10⁻³⁴ j·s and c = 3.00×10⁸ m/s)
answer: s⁻¹

Explanation:

Step1: Recall energy - frequency formula

The energy of a photon is given by $E = h
u$, where $E$ is energy, $h$ is Planck's constant, and $
u$ is frequency.

Step2: Solve for frequency

We can re - arrange the formula to $
u=\frac{E}{h}$.
Substitute $E = 7.07\times 10^{-19}\text{ J}$ and $h = 6.626\times 10^{-34}\text{ J}\cdot\text{s}$ into the formula:
$
u=\frac{7.07\times 10^{-19}\text{ J}}{6.626\times 10^{-34}\text{ J}\cdot\text{s}}$
$
u = 1.07\times10^{15}\text{ s}^{-1}$

Answer:

$1.07\times 10^{15}$