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Question
problem 2: after a bad year, trogans is reducing its workforce and renting out part of its office space. arra needed to find the new square feet per employee.
number of workers (workers)
workers laid off (workers)
workers last year (workers)
new square feet per worker (sq ft/worker)
new square feet (sq ft)
square feet renting out (sq ft)
square feet last year (sq ft)
problem 3: scramble chicken farms is interested in the productivity of each of its chickens over the last month. the steps needed to find the average eggs per chicken produced.
total eggs (eggs)
chickens per coop (chickens/coop)
number of coops (coops)
baskets of eggs (baskets)
average eggs per basket (eggs/basket)
total chickens (chickens)
total eggs (eggs)
eggs per chicken (eggs/chicken)
Problem 2
Step1: Calculate new worker count
$\text{new number of workers} = \text{workers last year} - \text{workers laid off}$
Step2: Calculate new office space
$\text{new usable square feet} = \text{square feet last year} - \text{square feet renting out}$
Step3: Compute sq ft per worker
$\text{new square feet per worker} = \frac{\text{new usable square feet}}{\text{new number of workers}}$
Problem 3
Step1: Get total eggs (direct or derived)
If using derived total eggs: $\text{total eggs} = \text{baskets of eggs} \times \text{average eggs per basket}$
Step2: Get total chickens (direct or derived)
If using derived total chickens: $\text{total chickens} = \text{chickens per coop} \times \text{number of coops}$
Step3: Compute eggs per chicken
$\text{eggs per chicken} = \frac{\text{total eggs}}{\text{total chickens}}$
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Problem 2 Final Calculation:
$\text{new square feet per worker} = \frac{\text{square feet last year} - \text{square feet renting out}}{\text{workers last year} - \text{workers laid off}}$
Problem 3 Final Calculation (using direct values):
$\text{eggs per chicken} = \frac{\text{total eggs}}{\text{total chickens}}$
Or (using derived values):
$\text{eggs per chicken} = \frac{\text{baskets of eggs} \times \text{average eggs per basket}}{\text{chickens per coop} \times \text{number of coops}}$